선형 대수 예제

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 (\sqrt{3})}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 (\sqrt{3})}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 (\sqrt{3})}{3} \end{array}] [\begin{array}{c} - \frac{1}{\sqrt{2}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 1

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - (\frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}) & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2

분모를 결합하고 간단히 합니다.

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단계 2.1

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{\sqrt{2} \sqrt{2}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.2

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.3

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.4

지수 법칙 $a^{m} a^{n} = a^{m + n}$ 을 이용하여 지수를 합칩니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{{\sqrt{2}}^{1 + 1}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.5

$1$ 를 $1$ 에 더합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{{\sqrt{2}}^{2}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.6

${\sqrt{2}}^{2}$ 을 $2$ 로 바꿔 씁니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 2.6.1

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ 을(를) 사용하여 $\sqrt{2}$ 을(를) $2^{\frac{1}{2}}$ (으)로 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{{(2^{\frac{1}{2}})}^{2}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.6.2

멱의 법칙을 적용하여 ${(a^{m})}^{n} = a^{m n}$ 과 같이 지수를 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2^{\frac{1}{2} \cdot 2}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.6.3

$\frac{1}{2}$ 와 $2$ 을 묶습니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2^{\frac{2}{2}}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.6.4

$2$ 의 공약수로 약분합니다.

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단계 2.6.4.1

공약수로 약분합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2^{\frac{2}{2}}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.6.4.2

수식을 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2^{1}} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 2.6.5

지수값을 계산합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{1}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 3

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4

분모를 결합하고 간단히 합니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 4.1

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{\sqrt{2} \sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.2

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.3

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.4

지수 법칙 $a^{m} a^{n} = a^{m + n}$ 을 이용하여 지수를 합칩니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{{\sqrt{2}}^{1 + 1}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.5

$1$ 를 $1$ 에 더합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{{\sqrt{2}}^{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.6

${\sqrt{2}}^{2}$ 을 $2$ 로 바꿔 씁니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 4.6.1

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ 을(를) 사용하여 $\sqrt{2}$ 을(를) $2^{\frac{1}{2}}$ (으)로 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{{(2^{\frac{1}{2}})}^{2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.6.2

멱의 법칙을 적용하여 ${(a^{m})}^{n} = a^{m n}$ 과 같이 지수를 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2^{\frac{1}{2} \cdot 2}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.6.3

$\frac{1}{2}$ 와 $2$ 을 묶습니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2^{\frac{2}{2}}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.6.4

$2$ 의 공약수로 약분합니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 4.6.4.1

공약수로 약분합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2^{\frac{2}{2}}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.6.4.2

수식을 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2^{1}} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 4.6.5

지수값을 계산합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{1}{\sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 5

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - (\frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}) & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6

분모를 결합하고 간단히 합니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 6.1

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{\sqrt{2} \sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.2

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.3

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.4

지수 법칙 $a^{m} a^{n} = a^{m + n}$ 을 이용하여 지수를 합칩니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{{\sqrt{2}}^{1 + 1}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.5

$1$ 를 $1$ 에 더합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{{\sqrt{2}}^{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.6

${\sqrt{2}}^{2}$ 을 $2$ 로 바꿔 씁니다.

자세한 풀이 단계를 보려면 여기를 누르십시오...

단계 6.6.1

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ 을(를) 사용하여 $\sqrt{2}$ 을(를) $2^{\frac{1}{2}}$ (으)로 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{{(2^{\frac{1}{2}})}^{2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.6.2

멱의 법칙을 적용하여 ${(a^{m})}^{n} = a^{m n}$ 과 같이 지수를 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2^{\frac{1}{2} \cdot 2}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.6.3

$\frac{1}{2}$ 와 $2$ 을 묶습니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2^{\frac{2}{2}}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.6.4

$2$ 의 공약수로 약분합니다.

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단계 6.6.4.1

공약수로 약분합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2^{\frac{2}{2}}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.6.4.2

수식을 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2^{1}} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 6.6.5

지수값을 계산합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 7

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8

분모를 결합하고 간단히 합니다.

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단계 8.1

$\frac{1}{\sqrt{2}}$ 에 $\frac{\sqrt{2}}{\sqrt{2}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{\sqrt{2} \sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.2

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.3

$\sqrt{2}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.4

지수 법칙 $a^{m} a^{n} = a^{m + n}$ 을 이용하여 지수를 합칩니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{{\sqrt{2}}^{1 + 1}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.5

$1$ 를 $1$ 에 더합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{{\sqrt{2}}^{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.6

${\sqrt{2}}^{2}$ 을 $2$ 로 바꿔 씁니다.

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단계 8.6.1

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ 을(를) 사용하여 $\sqrt{2}$ 을(를) $2^{\frac{1}{2}}$ (으)로 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{{(2^{\frac{1}{2}})}^{2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.6.2

멱의 법칙을 적용하여 ${(a^{m})}^{n} = a^{m n}$ 과 같이 지수를 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2^{\frac{1}{2} \cdot 2}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.6.3

$\frac{1}{2}$ 와 $2$ 을 묶습니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2^{\frac{2}{2}}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.6.4

$2$ 의 공약수로 약분합니다.

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단계 8.6.4.1

공약수로 약분합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2^{\frac{2}{2}}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.6.4.2

수식을 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2^{1}} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 8.6.5

지수값을 계산합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 9

$\frac{1}{\sqrt{3}}$ 에 $\frac{\sqrt{3}}{\sqrt{3}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{1}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10

분모를 결합하고 간단히 합니다.

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단계 10.1

$\frac{1}{\sqrt{3}}$ 에 $\frac{\sqrt{3}}{\sqrt{3}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{\sqrt{3} \sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.2

$\sqrt{3}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{{\sqrt{3}}^{1} \sqrt{3}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.3

$\sqrt{3}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{{\sqrt{3}}^{1} {\sqrt{3}}^{1}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.4

지수 법칙 $a^{m} a^{n} = a^{m + n}$ 을 이용하여 지수를 합칩니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{{\sqrt{3}}^{1 + 1}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.5

$1$ 를 $1$ 에 더합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{{\sqrt{3}}^{2}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.6

${\sqrt{3}}^{2}$ 을 $3$ 로 바꿔 씁니다.

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단계 10.6.1

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ 을(를) 사용하여 $\sqrt{3}$ 을(를) $3^{\frac{1}{2}}$ (으)로 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{{(3^{\frac{1}{2}})}^{2}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.6.2

멱의 법칙을 적용하여 ${(a^{m})}^{n} = a^{m n}$ 과 같이 지수를 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3^{\frac{1}{2} \cdot 2}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.6.3

$\frac{1}{2}$ 와 $2$ 을 묶습니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3^{\frac{2}{2}}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.6.4

$2$ 의 공약수로 약분합니다.

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단계 10.6.4.1

공약수로 약분합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3^{\frac{2}{2}}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.6.4.2

수식을 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3^{1}} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 10.6.5

지수값을 계산합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{1}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 11

$\frac{1}{\sqrt{3}}$ 에 $\frac{\sqrt{3}}{\sqrt{3}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{1}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12

분모를 결합하고 간단히 합니다.

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단계 12.1

$\frac{1}{\sqrt{3}}$ 에 $\frac{\sqrt{3}}{\sqrt{3}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{\sqrt{3} \sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.2

$\sqrt{3}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{1} \sqrt{3}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.3

$\sqrt{3}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{1} {\sqrt{3}}^{1}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.4

지수 법칙 $a^{m} a^{n} = a^{m + n}$ 을 이용하여 지수를 합칩니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{1 + 1}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.5

$1$ 를 $1$ 에 더합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{2}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.6

${\sqrt{3}}^{2}$ 을 $3$ 로 바꿔 씁니다.

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단계 12.6.1

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ 을(를) 사용하여 $\sqrt{3}$ 을(를) $3^{\frac{1}{2}}$ (으)로 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{(3^{\frac{1}{2}})}^{2}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.6.2

멱의 법칙을 적용하여 ${(a^{m})}^{n} = a^{m n}$ 과 같이 지수를 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{\frac{1}{2} \cdot 2}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.6.3

$\frac{1}{2}$ 와 $2$ 을 묶습니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{\frac{2}{2}}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.6.4

$2$ 의 공약수로 약분합니다.

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단계 12.6.4.1

공약수로 약분합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{\frac{2}{2}}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.6.4.2

수식을 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{1}} & \frac{1}{\sqrt{3}} \end{array}]$

단계 12.6.5

지수값을 계산합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{1}{\sqrt{3}} \end{array}]$

단계 13

$\frac{1}{\sqrt{3}}$ 에 $\frac{\sqrt{3}}{\sqrt{3}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{1}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} \end{array}]$

단계 14

분모를 결합하고 간단히 합니다.

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단계 14.1

$\frac{1}{\sqrt{3}}$ 에 $\frac{\sqrt{3}}{\sqrt{3}}$ 을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{\sqrt{3} \sqrt{3}} \end{array}]$

단계 14.2

$\sqrt{3}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{1} \sqrt{3}} \end{array}]$

단계 14.3

$\sqrt{3}$ 를 $1$ 승 합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{1} {\sqrt{3}}^{1}} \end{array}]$

단계 14.4

지수 법칙 $a^{m} a^{n} = a^{m + n}$ 을 이용하여 지수를 합칩니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{1 + 1}} \end{array}]$

단계 14.5

$1$ 를 $1$ 에 더합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{\sqrt{3}}^{2}} \end{array}]$

단계 14.6

${\sqrt{3}}^{2}$ 을 $3$ 로 바꿔 씁니다.

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단계 14.6.1

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ 을(를) 사용하여 $\sqrt{3}$ 을(를) $3^{\frac{1}{2}}$ (으)로 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{{(3^{\frac{1}{2}})}^{2}} \end{array}]$

단계 14.6.2

멱의 법칙을 적용하여 ${(a^{m})}^{n} = a^{m n}$ 과 같이 지수를 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{\frac{1}{2} \cdot 2}} \end{array}]$

단계 14.6.3

$\frac{1}{2}$ 와 $2$ 을 묶습니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{\frac{2}{2}}} \end{array}]$

단계 14.6.4

$2$ 의 공약수로 약분합니다.

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단계 14.6.4.1

공약수로 약분합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{\frac{2}{2}}} \end{array}]$

단계 14.6.4.2

수식을 다시 씁니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3^{1}} \end{array}]$

단계 14.6.5

지수값을 계산합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} \end{array}]$

단계 15

$[\begin{array}{c} - \frac{\sqrt{2}}{2} & - \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} & 0 & \frac{4 \sqrt{3}}{3} \\ 0 & \frac{\sqrt{2}}{2} & \frac{4 \sqrt{3}}{3} \end{array}] [\begin{array}{c} - \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} & 0 \\ - \frac{\sqrt{2}}{2} & 0 & \frac{\sqrt{2}}{2} \\ \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} & \frac{\sqrt{3}}{3} \end{array}]$ 을 곱합니다.

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단계 15.1

Two matrices can be multiplied if and only if the number of columns in the first matrix is equal to the number of rows in the second matrix. In this case, the first matrix is $3 \times 3$ and the second matrix is $3 \times 3$ .

단계 15.2

첫 번째 행렬의 각 행에 두 번째 행렬의 각 열을 곱합니다.

$[\begin{array}{c} - \frac{\sqrt{2}}{2} (- \frac{\sqrt{2}}{2}) - \frac{\sqrt{2}}{2} (- \frac{\sqrt{2}}{2}) + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} & - \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2} \cdot 0 + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} & - \frac{\sqrt{2}}{2} \cdot 0 - \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{2}}{2} + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} \\ \frac{\sqrt{2}}{2} (- \frac{\sqrt{2}}{2}) + 0 (- \frac{\sqrt{2}}{2}) + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} & \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{2}}{2} + 0 \cdot 0 + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} & \frac{\sqrt{2}}{2} \cdot 0 + 0 \frac{\sqrt{2}}{2} + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} \\ 0 (- \frac{\sqrt{2}}{2}) + \frac{\sqrt{2}}{2} (- \frac{\sqrt{2}}{2}) + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} & 0 \frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2} \cdot 0 + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} & 0 \cdot 0 + \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{2}}{2} + \frac{4 \sqrt{3}}{3} \cdot \frac{\sqrt{3}}{3} \end{array}]$

단계 15.3

모든 식을 전개하여 행렬의 각 원소를 간단히 합니다.

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단계 15.3.1

$4$ 에 $2$ 을 곱합니다.

$[\begin{array}{c} \frac{7}{3} & \frac{5}{6} & \frac{5}{6} \\ \frac{5}{6} & \frac{11}{6} & \frac{4}{3} \\ \frac{5}{6} & \frac{4}{3} & \frac{3 + 8}{6} \end{array}]$

단계 15.3.2

$3$ 를 $8$ 에 더합니다.

$[\begin{array}{c} \frac{7}{3} & \frac{5}{6} & \frac{5}{6} \\ \frac{5}{6} & \frac{11}{6} & \frac{4}{3} \\ \frac{5}{6} & \frac{4}{3} & \frac{11}{6} \end{array}]$